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Question 3 - ABC and DBC are two triangles on same base BC
Two triangles ABC and DBC lie on the same side of the base BC. From a point P on BC, PQ||AB and PR||BD are drawn. They meet AC in Q and DC
In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that Ar(ABC)Ar (DBC) = AODO
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The base BC of an equilateral triangle ABC lies on y - axis . The coordinates of the point C are (0, - 3). If the origin is the mid - point
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Question 3 - ABC and DBC are two triangles on same base BC
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